A train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km
Quadratic Equations (10)A train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete total journey, what is the original average speed ?
Answer
Let the original average speed of train be x km/hr. Therefore,
$$ \frac{63}{x} + \frac{72}{x + 6} = 3 $$
x2 - 39x - 126 = 0
(x - 42)(x + 3) = 0
$$ x \ne -3 $$
x = 42
Original speed of train is 42 km/hr.
Exam Year:
2018
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