Solve for x: $\frac{1}{x+1} +\frac{3}{5x+1} = \frac{5}{x+4}, x\ne-1, -\frac{1}{5}, -4$
Quadratic Equations (10)Solve for x:
$$ \frac{1}{x+1} +\frac{3}{5x+1} = \frac{5}{x+4}, x\ne-1, -\frac{1}{5}, -4 $$
Answer
[(5x + 1) + (x + 1)3](x + 4) = 5(x + 1) (5x + 1)
(8x + 4)(x + 4) = 5(5x2 + 6x + 1)
17x2 - 6x - 11 = 0
(17x + 11)(x - 1) = 0
$$ x = \frac{-11}{17}, x = 1 $$
Exam Year:
2017
Related Questions
- Which of the following is not a quadratic equation
- Assertion (A): If one root of the quadratic equation $4x^2 − 10x + (k − 4) = 0$
- A motor boat whose speed is 18 km/hr in still water takes 1hr more to go 24 km
- Find the discriminant of the quadratic equation $3x^2 -2x + \frac{1}{3} = 0$ and hence find the nature of its roots
- If the points A(k + 1, 2k), B(3k, 2k + 3) and C(5k - 1, 5k) are collinear, then find the value of k
- Two taps running together can fill a tank in 3$\frac{1}{13}$ hours