Solve for x: $\frac{1}{x+1} +\frac{3}{5x+1} = \frac{5}{x+4}, x\ne-1, -\frac{1}{5}, -4$
Quadratic Equations (10)Solve for x:
$$ \frac{1}{x+1} +\frac{3}{5x+1} = \frac{5}{x+4}, x\ne-1, -\frac{1}{5}, -4 $$
Answer
[(5x + 1) + (x + 1)3](x + 4) = 5(x + 1) (5x + 1)
(8x + 4)(x + 4) = 5(5x2 + 6x + 1)
17x2 - 6x - 11 = 0
(17x + 11)(x - 1) = 0
$$ x = \frac{-11}{17}, x = 1 $$
Exam Year:
2017
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