Find the sum of first 8 multiples of 3
Arithmetic Progressions (10)Find the sum of first 8 multiples of 3.
Answer
S = 3 + 6 + 9 + 12 + ... + 24
= 3(1 + 2 + 3 + ... + 8)
= 3 x $ \frac{8 \times 9}{2} $
= 108
Exam Year:
2018
Related Questions
- Which term of the Arithmetic Progression -7, -12, -17, -22, ... will be -82 ?
- In an AP, if the common difference (d) = -4, and the seventh term
- How many terms of the Arithmetic Progression 45, 39, 33, ... must be taken so that their sum is 180
- If the ratio of the sum of the first n terms of two A.Ps is (7n + 1) : (4n + 27)
- Which term of the progression $20, 19 \frac{1}{4},18\frac{1}{2} ,17\frac{3}{4}$... is the first negative term
- $ \frac{1}{a},\frac{3 - a}{3a},\frac{3 - 2a}{3a} ... (a \ne 0)$