If A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5) are the vertices of a quadrilateral
Coordinate Geometry (10)If A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
Answer
Area of quad ABCD = Ar ΔABD + Ar ΔBCD
Area of ΔABD = $\frac{1}{2}$ |(-5)(-5 - 5) + (-4)(5 - 7) + (4)(7 +5)|
= 53 sq units
Area of ΔBCD = $\frac{1}{2}$ | (-4)(-6-5)+ (-1)(5 +5)+4(-5+6)|
= 19 sq units
Hence, area of quad. ABCD = 53 + 19 = 72 sq units
- Exam Year: 2018
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