A 5 $\mathrm{\Omega }$ resistor is connected across a battery of 6 volts

A 5Ω resistor is connected across a battery of 6 volts. Calculate the energy that dissipates as heat in 10 s.

Answer

V = 6 V; R = 5Ω; t = 10 s

Energy dissipated as heat in t = 10 s is

$$𝐻=\frac{V^2}{R}t$$

$$=\frac{(6V^2)}{5\Omega }\times 10s$$

$$=72J$$