A 5 $\Omega$ resistor is connected across a battery of 6 volts
Electricity (10)A 5Ω resistor is connected across a battery of 6 volts. Calculate the energy that dissipates as heat in 10 s.
Answer
V = 6 V; R = 5Ω; t = 10 s
Energy dissipated as heat in t = 10 s is
$$ 𝐻 =\frac{V^2}{R}t$$
$$ = \frac{(6 V^2)}{5Ω} \times 10 s $$
$$ = 72 J $$
- Exam Year: 2022
Related Questions
- Consider the given circuit and find the current flowing in the circuit and potential difference
- List the factors on which the resistance of a conductor in the shape of a wire depends
- Write Joule’s law of heating
- Three resistors R1, R2 and R3 are connected in parallel and the combination is connected to a battery, an ammeter
- Two LED bulbs of 12W and 6W are connected in series
- The resistance of a resistor is reduced to half of its initial value