A 5 $\Omega$ resistor is connected across a battery of 6 volts

A 5Ω resistor is connected across a battery of 6 volts. Calculate the energy that dissipates as heat in 10 s.

Answer

V = 6 V; R = 5Ω; t = 10 s

Energy dissipated as heat in t = 10 s is

$$ 𝐻 =\frac{V^2}{R}t$$

$$ = \frac{(6 V^2)}{5Ω} \times 10 s $$

$$ = 72 J $$