A 5 $\Omega$ resistor is connected across a battery of 6 volts
Electricity (10)A 5Ω resistor is connected across a battery of 6 volts. Calculate the energy that dissipates as heat in 10 s.
Answer
V = 6 V; R = 5Ω; t = 10 s
Energy dissipated as heat in t = 10 s is
$$ 𝐻 =\frac{V^2}{R}t$$
$$ = \frac{(6 V^2)}{5Ω} \times 10 s $$
$$ = 72 J $$
Exam Year:
2022
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