Find the zeroes of the quadratic polynomial $ x^2 + 6x + 8 $
Polynomials (10)Find the zeroes of the quadratic polynomial $ x^2 + 6x + 8 $ and verify the relationship between the zeroes and the coefficients.
Answer
$$ x^2 + 6x + 8 = (x + 4)( x + 2) $$
Zeroes are -4, -2
Sum of zeroes
$$ –4 + (–2) = –6 = \frac{-6}{1} =\frac{\text{- Coeff. of x}}{\text{Coeff. of } x^2} $$
Product of zeroes
$$ (-4)(-2) = 8 = \frac{8}{1} = \frac{\text{Constant term}}{\text{Coeff. of } x^2} $$
Exam Year:
2023