Given $\Delta ABC \sim \Delta PQR$, if $\frac{AB}{PQ} =\frac{1}{3}$
Triangles (10)Given $ \Delta ABC \sim \Delta PQR, if \frac{AB}{PQ} = \frac{1}{3}$, then find $\frac{ar\Delta ABC}{ar\Delta PQR}$
Answer
$$\frac{ar\Delta ABC}{ar\Delta PQR} $$
$$ = \frac{AB^2}{PQ^2}$$
$$ = \left(\frac{1}{3}\right)^2 = \frac{1}{9} $$
- Exam Year: 2018
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